What is the slope of the line through the points (X1, Y1) and (X2, Y2)?
The slope of a line is the amount of change in the y-coordinate as the x-coordinate increases by one unit.
The equation for the slope is:
\qquad m = \dfrac{\blue{y_2} - \purple{y_1}}{\blue{x_2} - \purple{x_1}}
Substitute the values for
(\purple{X1}, \purple{Y1}) and
(\blue{X2}, \blue{Y2}):
\qquad m = \dfrac{\blue{Y2} - \purple{negParens(Y1)}}
{\blue{X2} - \purple{negParens(X1)}} =
\dfrac{\green{Y2 - Y1}}{\pink{X2 - X1}}
So, the slope m is fractionReduce( Y2 - Y1, X2 - X1 ).
Which graph best depicts a slope of M.display?
\quad \color{COLORS[WHICH].hex}{\text{COLORS[WHICH].name}}\quad \color{COLORS[index].hex}{\text{COLORS[index].name}}
A slope of M.display means that the y-coordinate changes by M.display
as the x-coordinate increases by one unit.
The \color{COLORS[WHICH].hex}{\text{COLORS[WHICH].name.toLowerCase()}}
graph has a slope of M.display.
The other graphs have slopes of toSentence(OTHER_SLOPES).
Which graph best depicts a slope of M.display?
Which graph best depicts an undefined slope?
A slope of M.display means the
y-coordinate doesn't change at all as the x-coordinate changes.
A vertical line has an undefined slope.
The x-coordinate doesn't change,
so if we try to calculate the slope between two points with
m = \dfrac{\blue{y_2} - \purple{y_1}}{\blue{x_2} - \purple{x_1}},
we'll have to divide by zero!
The \color{COLORS[WHICH].hex}{\text{COLORS[WHICH].name.toLowerCase()}}
graph depicts an undefined slope.
The \color{COLORS[WHICH].hex}{\text{COLORS[WHICH].name.toLowerCase()}}
graph depicts a slope of M.display.